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Posts: 5
Joined: Thu Feb 08, 2018 11:08 pm
Name: Kailey Truscott

When $$a \ne 0$$, there are two solutions to $$ax^2 + bx + c = 0$$ and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$$
When $a \ne 0$, there are two solutions to $ax^2 + bx + c = 0$ and they are $x = {-b \pm \sqrt{b^2-4ac} \over 2a}$